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iren [92.7K]
3 years ago
10

The sum of the digits of a two digit number is 6z the number with its digits reversed is 18 less than the original number. Find

the original number
Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

42

Step-by-step explanation:

Given:-

The Sum of the Digit of a Two Digit number is 6.

On reversing, the number is 18 less than the original number.

To Find:-

The original Number.

Let the Ones digit be "x"

ten's digit be = (6 - x)

Original Number = x + 10(6 - x) = 60 - 9x

Now, Atq.

One's Digit = (6 - x)

Ten's digit = x

New Number = 10 × x + (6 - x) = 9x + 6.

So,

(New Number) - (Original Number) = 18

(9x + 6 ) - (60- 9x) = 18

9x + 6 - 60 + 9x = 18

18x - 54 = 18

18x = 18 + 54.

18x = 72

x = 72/18

x = 4.

Therefore,

One's Digit = x = 4

Ten's digit = 6 - x = 2

Original Number = 42

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The expression below is the factorization of what trinomial-1(x+5)(x+6)
Nadya [2.5K]

Answer:

-x^2 - 11x -30

Step-by-step explanation:

Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.

ie: x(x) and x(6)

ie: x^2 + 6x

Then do the 5 times the things in the second parenthesis.

ie: 5(x) and 5(6)

ie: 5x + 30

Then add what you got from multiplying the first value to what you got from multiplying the second.

ie: x^2 + 11x + 30

This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.

ie: -x^2 - 11x -30

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Step-by-step explanation:

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