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Marizza181 [45]
3 years ago
14

HURRY THIS IS TIMED. I WILL GIVE BRANIEST IF CORRECT. EXPLAIN YOUR ANSWER!! THX

Mathematics
2 answers:
Aleks [24]3 years ago
4 0

Answer: A and c

Step-by-step explanation: because they are the only ones that have p,x,m and not just seperate.

MissTica3 years ago
4 0
Correct answers are A and C
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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Need Help!
Contact [7]

Answer:

4) Alternate  Interior angles 5) Parallel lines property.

Step-by-step explanation:

The question is asking us to Complete the statements to prove that line AB ⩭ to line CD and line BC ⩭ to line AD.

In statement 4 .∠CAB is congruent to ∠ACD as AB is parallel to CD  and ∠BCA  is congruent to∠CAD as AD is parallel to BC  and these are Alternate interior angles to the parallel lines .

In statement 5.m∠CAB =∠ACD and ∠BCA = ∠CAD as by property of parallel lines Alternate interior angles are equal.

6 0
3 years ago
Read 2 more answers
Help pleaseee mathhhhhh
dimaraw [331]

Answer:

hehjzjxjxjdjjdhdhdhdhjdjdjhdhdhdhdjdjjdjsjs B is correct

5 0
3 years ago
2 horses ran from the same place from the at same time one horse ran at 2 miles per second and the other ran at a speed for 18 m
RSB [31]

Answer:

no horse can run 18 miles per second or even 2 miles per second.

Step-by-step explanation:

4 0
3 years ago
Answer my math question I asked so many times I lost most of points by
kumpel [21]

Answer:

i think ur in a higher grade then me but im good w/ equations so OoOO0p

Step-by-step explanation:

equation: y = x - 6 + x^2

(6,0) (7,1) (8,4) (9,9)

I figured this out by looking at the point (6,0). To get 0 (y), you have to subtract 6. Knowing this, I subtracted 6 from the rest of the coordinates, leaving me with numbers that are able to be squared to get y. This led me to the equation x - 6 + x^2.

8 0
3 years ago
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