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3 years ago

What is system of linear equation means?

Mathematics

2 answers:

alex41 [277]3 years ago

8 0

Answer: A linear equation in one variable is an equation that can be written in the form

aX + b = )

Where a ≠ 0

For example

2x + 6 = 0

irina1246 [14]3 years ago

4 0

A system of linear equations is just a set of two or more linear equations. In two variables (x and y) , the graph of a system of two equations is a pair of lines in the plane.

Step-by-step explanation:

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For each sequence, determine whether it appears to be

Airida [17]

Answer:

I think the answer is neither

7 0

4 years ago

A car salesman sold two cars worth a total of $67,500. He was paid a commission of $2,025. What percent was this?

Fofino [41]

Answer:

280%

Step-by-step explanation:

67,500 divided by 2,025 is 280.25

4 0

3 years ago

A factory makes 1200 pounds of potato chips in 4 hours. At this rate, how many pounds of chips will the factory make in 10 hours

Snowcat [4.5K]

Use a proportion for this one.

1200/4 = x/10

x will equal A. 3000

Please brainliest me if this helped; trying to level up!

8 0

4 years ago

Read 2 more answers

Which expression is equivalent to the one below<br><br>(X^2y)(x^4y^3)/xy^2

Ilya [14]

The last option.
(x^6)(y^4)/(xy^2).

6 0

3 years ago

You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. You samp

MariettaO [177]

Answer:

Given:You sample 160 men, and 25% own cats

You sample 120 women, and 20% own cats.

To Find : Find the test statistic, rounded to two decimal places.

Solution:

You sample 160 men, and 25% own cats.

No. of men have cats = $\frac{25}{100} \times 160$

= $40$

So, $n_1=160 , y_1=40$

You sample 120 women, and 20% own cats.

No. of women have cats = $\frac{20}{100} \times 120$

= $24$

So, $n_2=120 , y_2=24$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{40}{160}$

$\widehat{p_1}=0.25$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{24}{120}$

$\widehat{p_2}=0.2$

Let $p_1$ and $p_2$ be the probabilities of men having cat and women having cat receptively

$H_0:p_1=p_2\\H_a:p_1$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}$

test statistic : $0.986$

So, test statistic is 0.986

8 0

4 years ago