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Ainat [17]
2 years ago
14

Isaac orders dried fruit from an online health food store. He pays a price per pound for the fruit, and a flat shipping fee. Thi

s table shows the total cost for different amounts of fruit ordered.What is the most reasonable domain and range for the situation?
Mathematics
1 answer:
Tasya [4]2 years ago
3 0

Answer:

Step-by-step explanation:

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How do you write 39/10 as a percentage?
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39/10

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You find 72 coins consisting only of nickels, dimes, and quarters, with a face value of $10.20. However, the coins all date from
Oliga [24]

Answer:

You have found 24 nickels.

Step-by-step explanation:

Let N be the number of nickles, D be the number of dimes and Q be the number of quarters. The number of coins and their face values are given by the following expressions, respectively:

N+D+Q=72\\0.05N+0.10D+0.25Q=10.20

As of now we have three variables and two expressions, the final expression needed to solve the linear system is given by the amount offered by the coin dealer:

10N+20D+15Q=1,060

Solving the linear system:

N+D+Q=72\\5N+10D+25Q=1,020\\10N+20D+15Q=1,060\\\\10N-10N+20D-20D+15Q-50Q=1,060-(2*1,020)\\-35Q=-980\\Q=28\\\\5N-10N+10D-10D+25Q-10Q=1,020-720\\-5N+15Q=300\\-5N=300-(15*28)\\N=24

You have found 24 nickels.

7 0
2 years ago
A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?​
zzz [600]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf 240 \:  {inches}^{2} }}}}

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

\boxed{ \sf{perimeter = 2(l + w)}}

plug the values

⇒\sf{64 = 2(20 + w)}

Distribute 2 through the parentheses

⇒\sf{64 = 40 + 2w}

Swap the sides of the equation

⇒\sf{40 + 2w = 64}

Move 2w to right hand side and change it's sign

⇒\sf{2w = 64 - 40}

Subtract 40 from 64

⇒\sf{2w = 24}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{24}{2} }

Calculate

⇒\sf{w = 12 \: inches}

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

\boxed{ \sf{area \: of \: rectangle = length \:  \times  \: \: width}}

plug the values

⇒\sf{area \: of \: rectangle =20 \times  12 }

Multiply the numbers : 20 and 12

⇒\sf{area \: of \: rectangle = 240 \:  {inches}^{2} }

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0
3 years ago
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