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laila [671]
3 years ago
9

-(r+4) = -3 Solve each equation. Please explain step by step so i can understand!

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

-\left(r+4\right)=-3

First, Divide both sides by -1,

\frac{-\left(r+4\right)}{-1}=\frac{-3}{-1}

r+4=3

Then Subtract 4 from both sides,

r+4-4=3-4

r=-1

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In total there are 25 students in the class.

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If cot(theta)= 4/3, find csc(theta) (Picture provided)
kozerog [31]

Answer:

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Step-by-step explanation:

If \cot \theta=\dfrac{4}{3}, then we can consider right triangle with adjacent leg 4 un. and opposite leg 3 un.. By the Pythagorean theorem,

\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{hypotenuse}^2=4^2+3^2,\\ \\\text{hypotenuse}^2=16+9,\\ \\\text{hypotenuse}^2=25,\\ \\\text{hypotenuse}=5\ un.

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6 0
3 years ago
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Helga [31]

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8 0
3 years ago
*EXTRA POINTS* pls answer all of these
kvasek [131]

What do the two variables represent?

The two variables represent the number of nights or squires at the jousting contest.

Write a system of equations.

let k = number of knights and let s = number of squires

3k + 2s = 32

2k + s = 19

How many knights are there? <u>6</u>

How many squires are there? <u>7</u>

Solving:

solve for s in the second equation by subtracting 2k from both sides

2k + s = 19

s = 19 - 2k

substitute into first equation

3k + 2(19-2k) = 32

distribute 2 into 19-2k

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add like terms

-k + 38 = 32

subtract 38 from both sides

-k = -6

divide by -1

k = 6

subsitute into the equation for s

s = 19 - 2k

s = 19 - 2(6)

s = 19 - 12

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3 years ago
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3 years ago
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