3 1/5 ÷(z− 1/2 )=2 2/3 ÷(z+ 1/3 )
2 answers:
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We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then
Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer