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Ostrovityanka [42]
3 years ago
10

Increasing the average speed of a car by 12mph results in a 189 mile trip taking an hour less than before. What was the original

speed of the car?
Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
To answer this item, we let the original speed of the car be x. The time it take to travel a certain distance is calculated by dividing the distance by the speed. Using the condition given above,
                                 189 / (x + 12) = 189/x - 1
The value of x from the equation is 42 mph. Thus, the original speed of the car is 42 mph. 
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3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
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Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
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2. For the interval \frac{5}{3} < x < 5:
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3. For the interval x > 5:
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After simplifying, we get 13 > 0, which is ture.
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Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

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4 years ago
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Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

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(x + 3)(x - 4) ≠ 0

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