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3 years ago

A bottle of shampoo was on sale for $6.45.

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

$7 for the first question

$6.50 for the last one

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LOOK RIGHT HERE! HELP FASSST EMERGENCY! Don't go past go to this question right here and no Decimal answers plz. Thanks the answ

ArbitrLikvidat [17]

Answer: 140cm^3

Step-by-step explanation:

7 0

3 years ago

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the expe

elena55 [62]

Sarah rolled a one 3 times and rolled a three 1 time in a total of 20 rolls. She rolled one or three 4 times out of 20. Therefore,

$\frac{4}{20} = 0.2$

The answer is A.

4 0

4 years ago

A square has sides with lengths of (x - 2) units. A rectangle has a length of x units and a width of

vagabundo [1.1K]

Answer:

(A)The area of the square is greater than the area of the rectangle.

(C)The value of x must be greater than 4

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

Step-by-step explanation:

The Square has side lengths of (x - 2) units.

Area of the Square

$(x-2)^2=(x-2)(x-2)=x^2-2x-2x+4\\=(x^2-4x+4) \:Square \:Units$

The rectangle has a length of x units and a width of (x - 4) units.

Area of the Rectangle = $x(x-4)=(x^2-4x) \:Square \:Units$

The following statements are true:

(A)The area of the square is greater than the area of the rectangle.

This is because the area of the square is an addition of 4 to the area of the rectangle.

(C)The value of x must be greater than 4

If x is less than or equal to 4, the area of the rectangle will be negative or zero.

(E)The area of the rectangle is $(x^2-4x) \:Square \:Units$

3 0

3 years ago

A ÷ (2 + 1.5) for a = 14 dont spam links and this is 6th grade work

IRINA_888 [86]

Answer:

Step-by-step explanation:

2+1.5=3.5

49/3.5=14

4 0

2 years ago

Read 2 more answers

Select all polynomials that are divisible by (x-1)(x−1)left parenthesis, x, minus, 1, right parenthesis. Choose all answers that

alexdok [17]

Answer:

Step-by-step explanation:

For us to be able to determine the polynomials that are divisible by (x-1), this means that x-1 must be a factor for the functon to be able to divide any of the polynimial.

Since x-1 is a factor, we can get the value of x

x-1 = 0

x =0+1

x = 1

Next is for to substitute x - 1 into the polynomial and see the ones that will give us zero

For A(x)=3x^3+2x^2-x

A(1) = 3(1)^3+2(1)^2-(1)

A(1) = 3+2-(1)

A(1) = 5-1

A(1) = 4

Since A(1) ≠ 0, then x-1 is not divisible by the polynomial function.

For B(x)=5x^3-4x^2-x

B(1)=5(1)^3-4(1)^2-1

B(1)=5-4-1

B(1)=1-1 = 0

Since B(1) = 0, hence x-1 is divisible by 5x^3-4x^2-x

For the polynomial C(x)= 2x^3-3x^2+2x-1

C(1)=2(1)^3-3(1)^2+2(1)-1

C(1)=2-3+2-1

C(1)= -1+1

C(1)= 0

Since C(1) = 0, hence x-1 is divisible by the

For the polynomial D(x)=x^3+2x^2+3x+2

D(1)=1^3+2(1)^2+3(1)+2

D(1)=1+2+3+2

D(x) = 8

Hence the polynomial D(x) is not divisible by x-1

Hence the correct options are B(x)=5x^3-4x^2-x and 2x^3-3x^2+2x-1

8 0

4 years ago