Angle KMQ and angle RNL are on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles. Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.
a) 
because it is equal to the area of the shaded region between X=4 and X=6, and the probability that X falls within some interval is given by the area under the PDF.
b) 
because the shaded region is a rectangle of height 1/5 (by virtue of X following a uniform distribution over the interval [2, 7], which has length 5).
Answer:
225 frogs
Step-by-step explanation:
Total population of frogs = 300 frogs.
Observed population of frogs = 24
6 of the 24 observed frogs had spots
Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.
We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.
If 24 frogs = 18 frogs with no spots
300 frogs = Y
Cross multiply
24Y = 300 × 18
Y = (300 × 18) ÷ 24
Y = 5400 ÷ 24
Y = 225 frogs.
This means out of 300 frogs, 225 frogs do not have spots.
Therefore, the total population that can be predicted to NOT have spots is 225 frogs.
the total population can be predicted to NOT have spots
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
The numbers can include; 4.1, 4.2, 4.3, 4.4, 4.5, etc.
