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posledela
3 years ago
8

There is 3 red marbles, 7 white marbles, and 5 blue marbles. You draw 3 marbles replacing each one before drawing the next. What

is the probability of drawing a red marble, then a blue marble, and then a white marble?
Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

The jar contains 3+7+5=15 marbles in total.

We have to find the probability of the following events:

1. We choose a red marble from the jar that contains 15 marbles in total, 3 of them are red

2. We choose a blue marble from the jar that contains 15 marbles in total, 5 of them are blue

3. We choose a white marble from the jar that contains 15 marbles in total, 7 of them are white

The probability of the first event to happen is:

P_1=\frac{3}{15}=\frac{1}{5}

The probability of the second event to happen is:

P_2=\frac{5}{15}=\frac{1}{3}

The probability of the third event to happen is:

P_3=\frac{7}{15}

The probability of all three events to happen is:

P=P_1\cdot P_2\cdot P_3=\frac{1}{5}\cdot \frac{1}{3}\cdot \frac{7}{15}=\frac{7}{225}=0.0311

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4 0
3 years ago
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Brilliant_brown [7]

Answer:

Step-by-step explanation:

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