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Anna71 [15]
3 years ago
7

8. The expression (x+5)(x+8)+(x+5)(2x - 3) can be written as the product of (x + 5) and

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

(x + 5)(3x + 5)

Step-by-step explanation:

(x - 5)(x + 8) + (x + 5)(2x - 3) ← factor out (x + 5) from each term

= (x + 5)(x + 8 + 2x - 3)

= (x + 5)(3x + 5)

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BlackZzzverrR [31]

Answer:

9. A. One - to - One Correspondence

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Help me with my math quiz from friday 4/1 <br> SHOW STEPS
malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

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4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

\rightarrow\sf{7x - 4=87}

\rightarrow\sf{7x =87+4}

\rightarrow\sf{7x =91}

\rightarrow\sf{x =\frac{91}{7}}

\rightarrow\boxed{\bf{x =13}}

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5. radius = 17ft

circumference of circle = 2πr

\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}

\rightarrow\boxed{\bf{circumference=106.8ft}}

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3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

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2. 160° + (6x - 16)° = 180° (linear pair)

\rightarrow\sf{6x - 16 = 180-160}

\rightarrow\sf{6x - 16 = 20}

\rightarrow\sf{6x = 20+16}

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8 0
2 years ago
A line has a slope of 7 and passes through the point (-2,-1) What is its equation in point-slope form?
elena-s [515]

Answer:

y + 1 = 7(x + 2).

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Point slope form:

y - y1 =m(x - x1).

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So the answer is;

y - (-1) = 7(x - (-2))

5 0
3 years ago
What is the value of x in the equation x+7=−213 x+7=−2
MariettaO [177]

Answer:

Step-by-step explanation:

⅓x + 7 = -2

isolate the x term by subtracting 7 from both sides

⅓x = -9

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6 0
3 years ago
A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st
SpyIntel [72]

Answer:  15.3\pm0.198

OR

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval(\mu) is given by :-

\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

, where n is the sample size

s = sample standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha .

Given : Confidence level = 95% = 0.95

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sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , \sigma=1.6

By standard normal  distribution table ,

Two tailed z-value for Significance level of 0.05 :

z_{\alpha/2}=z_{0.025}=1.96

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

5 0
4 years ago
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