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3 years ago

Which of these changes in today's world is a product of advances in biology?

1 answer:

5 0

"Increased crop yields" is the one change in today's world among the choices given in the question that is a product of advances in biology. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has come to your desired help.

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20 points to whoever answers the questions in picture!

Rina8888 [55]

The unit rate is 4/5 or .8. Simply divide 4/5, and then use that to find your other answers. 3/.8=3 3/4 6 1/4* .8= 5.

4 5
3 3 3/4
5 6 1/4

5 0

3 years ago

Which expression is equivalent to r to the 9th over r to the 3rd

alisha [4.7K]

Answer:

$r^{6}$

Step-by-step explanation:

To make this a bit easier to see, we'll expand that expression.

R to the 9th is just r times itself 9 times. R to the third is r times itself 3 times.

(excuse my bad formatting)

The expression:

r • r • r • r • r • r • r • r • r • 1

r • r • r • 1

Remember, anything and everything has a coefficient or denominator of 1.

So, we can cancel 3 r's from the numerator and denominator.

r • r • r • r • r • r • 1

Simplify....

$\frac{1r^{6}}{1}$

That just equals $r^{6}$ .

3 0

3 years ago

Simplify 10 divided by 7 divided by 8 and put it in a fraction please :)

NeX [460]

Answer:5/28

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Choose the system of equations which makes the following graph:

solmaris [256]

(5 | -2) should be the solution of the equations

So it workt for c)

3*(5) - 5*(-2) = 25

(5) + 5*(-2) = -5

6 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago