V=x³-7x+6, V=(x-2)(x+3)*h
(x-2)(x+3)*h=x³-7x+6
h{x²+x-6}=x³-7x+6
h=(x³-7x+6)/(x²+x-6)
Therefore h=x-1
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Check answer:
V=(x-2)(x+3)(x-1)
=(x-1)(x²+x-6)
=x(x²+x-6)-1(x²+x-6)
=x³+x²-6x-x²-x+6
=x³-6x-x+6
=x³-7x+6
The left sum would be f0+f1+f2+f3
The right sum would be f1+f2+f3+f4
The trapezoidal rule value is:
(f0+f1)/2 + (f1+f2)/2+(f2+f3)/2 +(f3+f4)/2
This would put the trapezoidal rule in the middle , which makes the answer:
Lower sum < Trapezoidal rule Value < Upper sum
Answer:
(x+6)(x−6)=0
x=-6 or x=6
Step-by-step explanation:
X^2 - 36 = 0
Solve by Square Root
add 36 both sides
x^2−36+36=0+36
x^2=36
square root
x=±√36
x=6 or x=−6
You can do that or for 2nd option
Solve by factoring
x^2-36=0
(x+6)(x−6)=0
Set factors equal to 0
x+6=0 or x−6=0
x=-6 or x=6
PLEASE NOTE: 36 is the square of 6
and
x2 is the square of x1
Answer:
22.5km per hour
Step-by-step explanation:
