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svetoff [14.1K]
3 years ago
8

Find the price per unit for each item, then choose the best buy. a. Cereal, 10 oz. box for $5.90 would b. Cereal, 24 oz. box for

$ 6.48 would The best buy would be
Mathematics
2 answers:
hram777 [196]3 years ago
8 0
Okay so we can try to find how much it’d cost per ounce to see which one would give us the best deal
5.90/10= .59 per ounce

6.48/24= .27

therefore, the 24 oz. box would give us the best deal
Taya2010 [7]3 years ago
4 0

Cereal A

10 ounces = $5.90

10/10 ounces = $5.90/10 .... divide both sides by 10

1 ounce = $0.59

1 ounce = 59 cents

----------

Cereal B

24 ounces = $6.48

24/24 ounces = $6.48/24  .... divide both sides by 24

1 ounce = $0.27

1 ounce = 27 cents

We see that Cereal B is the cheaper deal per ounce

---------

<h3>Answer: Cereal B is the better deal</h3>
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Answer:

Assuming the numerator was 1.

(6\sqrt{7}+1)/251

Step-by-step explanation:

Assuming the numerator was 1.

1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251

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ddd [48]
If the number of adult tickets are taken as x then the number of children’s tickets can be taken as (89 — x ) then we can set up the equation

4.10(x) + 2.70 (89 — x) = 331.30
4.10x + 240.3 — 2.70x = 331.30
1.4x = 331.30 — 240.30
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Write an equation for this word<br> sentence: one fifth of a number<br> equals 16.
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y = c1 cos(5x) + c2 sin(5x) is a two-parameter family of solutions of the second-order DE y'' + 25y = 0. If possible, find a sol
TEA [102]

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

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4 years ago
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