The probability that among four randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.979.

Step-by-step explanation:

Since 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot.

Therefore, the Probability of 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot is, p=0.62.

We have to find the probability that at least one user is more careful about personal information when using wi-fi hotspot.

Probability of internet users are not more careful about personal information when using a public wi-fi hotspot, i.e $q=1-p$

$q=1-0.62=0.38$

Use Binomial Distribution, i.e, $P\left ( X \right )=^nC_xp^xq^\left ( n-x \right )$

p=0.62, q=0.38, n=4.

Required Probability $P\left ( X\geq 1 \right )=P\left ( X=1 \right )+P\left ( X=2 \right )+P\left ( X=3 \right )+P\left ( X=4 \right )$

$P\left ( X\geq 1 \right )=1-P\left ( X=0 \right )$

=1- $^4C_0p^0q^\left ( 4-0 \right )$

=1- $4\cdot1\cdot q^\left ( 4-0 \right )$

=1- $4\cdot \left ( 0.38 \right )^4$

=1-0.02085136=0.97914864

Therefore, the probability that at least one users more careful about personal information when using wi-fi hotspot, i.e 0.979(approx).

RESULT:

The result should not be impacted by this because volunteers are likely to have the most relevant responds.

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3 years ago

Using algbera solve 80 divide 10​

Using algbera solve 80 divide 10