Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
25°
Step-by-step explanation:
These types of figures have 3 angles, which add up to 180°. If you found the 2 angles already, you can find the last one by adding both angles together and using 180° to deduct it with the total degree of thd 2 angles.
127 + 28 = 155
180 - 155 = 25
Answer:
right triangle
Step-by-step explanation:
<u>Answer:</u>
<u>20,000 packages.</u>
<u>Step-by-step explanation:</u>
The rest of the question is as following:
If x represents the number of packages of dog treats, how many packages do they have to sell to break even? Round your answer to the nearest whole number, and do not include units.
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The function of fixed and variable costs ⇒ C(x) = 1.4x + 2000
The function of revenue ⇒ R(x) = 1.5x
The even situation will happen when costs = revenue
∴ C(x) = R(x)
∴ 1.4 x + 2000 = 1.5x
Solve for x:
∴ 1.5x - 1.4x = 2000
∴ 0.1 x = 2000
∴ x = 2000/0.1 = 20,000
The even will happen when they sell <u>20,000</u> packages
So, To break even, they have to sell more than 20,000 packages .