$Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}$

6 0

3 years ago

What is the slope of this line?

PIT_PIT [208]

Answer:

It has a slope of 1.

Step-by-step explanation:

First, you need to choose two points. The points HAS to be exactly on top of the line.

The two points I picked where

(-2,0) and (-1,1)

All you do is subtract the two points. Remember rise over run or y/x

1 -0 = 1

-1 - (-2) = 1

6 0

3 years ago

What is the square root of 69

Maurinko [17]

8
is the answer because8 times 8 equal 69

4 0

3 years ago