Answer:
Steady
Explanation:
Its not an insane growth rate but it would more then likely be Steady.
Answer:
It is the very last statement (bottom). Also copied to the the client
Explanation:
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
Answer:
class Simple{
public static void main(String args[]){
System.out.println("Hello Daddy and Mum);
}
}
Explanation:
First, we create a class, then a method and then give the Integrated Data Environment (IDE) the command to give out an output that says Hello, Daddy and Mum”
Answer: 10 students
Explanation:
Students younger than 10 = 50%
Students that are 10years old = 1/20 = 1/20 × 100 = 5%
Students that are older than 10 but younger than 12 = 1/10= 1/10 × 100 = 10%
Students that are 12 years or older
= 100% - (50% + 5% + 10%)
= 100% - 65%
= 35%
This means that 35% of the students are 12 years or older and we've been given the number as 70.
Let's say the total number of students is x. Therefore,
35% of x = 70
0.35 × x = 70
0.35x = 70
x = 70/0.35
x = 200
The total number of students is 200.
Therefore, the number of students that are 10years will be:
= 1/20 × 200
= 10 students
Therefore, 10 students are 10 years.
