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gizmo_the_mogwai [7]
2 years ago
11

Which side lengths form a right triangle?

Mathematics
2 answers:
saw5 [17]2 years ago
8 0
B
because
{1}^{2} + {8}^{2} = {( \sqrt{65}) }^{2}
ludmilkaskok [199]2 years ago
5 0
If you get a true statement when you simplify, then you do indeed have a right triangle! If you get a false statement, then you can be sure that your triangle is not a right triangle. Check out this tutorial and learn how use the Pythagorean theorem to see if a triangle is a right triangle!
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Find the value of pq - r/4 when p= -8 and q= -3 and r= 68
andrey2020 [161]

Answer:

7

Step-by-step explanation:

pq - r/4

(-8)(-3) - 68/4

-8 x -3 = 24 (2 negatives equal a positive)

24 - 68/4

68/4 = 17

24-17 = 7

6 0
3 years ago
Help I WILL GIVE BRAINLIEST
const2013 [10]

Answer:

16.6

Step-by-step explanation:

8 0
3 years ago
I’m not sure which one it is.
Fofino [41]

Answer: the answer is A) AC~=FC

Step-by-step explanation:

to answer that both triangles are congruent using SSS (Side-side-side) postulate, you have to show that each corresponding side is the same.

4 0
2 years ago
I need some help please! ^_^
Degger [83]
Perpendicular lines will have negative reciprocal slopes. What that means is if u have a slope of 1/2, to find the negative reciprocal, flip the slope and change the sign.......flip 2/1, change the sign -2/1 or just -2. So the negative reciprocal for the slope of 1/2 is -2. 

A. y = 1/5x + 3.....slope here is 1/5, so for a perpendicular line, u r gonna need an equation with the slope of -5.....and that would be : y + 3 = -5(x + 2).

B. Parallel lines will have the same slope. y = 5x - 2...the slope here is 5...so a parallel line will have a slope of 5.

y = mx + b
slope(m) = 5
(8,-2)...x = 8 and y = -2
now we sub, we r looking for b, the y intercept
-2 = 5(8) + b
-2 = 40 + b
-2 - 40 = b
-42 = b

so ur parallel equation is : y = 5x -42
7 0
3 years ago
Assignment The operation teeter is defined on the set T= { 2, 3, 5, 7 } by x teeter y=[x+y+xy) mod.8 a - Construct mod.8 table f
rosijanka [135]

Answer:

Case A) tau_net = -243.36 N m, case B)    tau_net = 783.36 N / m,      tau_net = -63.36 N m,  case C)  tau _net = - 963.36 N m,

Explanation:

For this exercise we use Newton's relation for rotation

        Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

        tau_net = m g x - F x2

         tau_nett = -28.8 9.8 1.5 + 180 1

        tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

the force is up

         tau_nett = -28.8 9.8 1.5 - 180 2

         tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 2

        tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

tau_nett = -28.8 9.8 1.5 - 180 3

tau _net = - 963.36 N m

3 counterclockwise

      tau_nett = -28.8 9.8 1.5 + 180 3

      tau_net = 116.64 Nm

the sitam rotated counterclockwise

<h3><u><em>Cr: moya1316</em></u></h3>
4 0
1 year ago
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