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Scilla [17]
3 years ago
7

The answer for the length width and square feet

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

whats the drawing.

Step-by-step explanation:

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How do you do the number line of this question why do we need to flip the inequality
Phantasy [73]
I don't see an inequality, but I can tell you that the sign of the inequality is flipped whenever you multiply or divide by a negative number.
8 0
4 years ago
Given vectors u = ⟨2, –3⟩ and v = ⟨1, –1⟩, what is the measure of the angle between the vectors?
oksano4ka [1.4K]

Answer:

The measure of the angle between the vectors = Ф = 11.30°

Step-by-step explanation:

Given

  • u = ⟨2, –3⟩
  • v = ⟨1, –1⟩

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

Next, find the lengths of the vectors:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

u = ⟨2, –3⟩

\:\:\left|u\right|\:=\sqrt{2^2+\left(-3\right)^2}

     =\sqrt{13}

u = ⟨2, –3⟩

|v|=\sqrt{1^2+\left(-1\right)^2}

    =\sqrt{2}

Finally, the angle is given by:

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

cos (Ф) = 5/√26

Ф = arc cos (cos (Ф)) = arc cos (5 √26) / (26)

Ф = 11.30°

Thus, the measure of the angle between the vectors = Ф = 11.30°

6 0
3 years ago
Read 2 more answers
Mason and Laney ran laps to train for the long-distance running team. The ratio of the number of laps Mason ran to the number of
AURORKA [14]
The answer is 21. It’s obvious.
6 0
3 years ago
In each problem below, find the total area of the shaded regions.<br> Thanks!
nika2105 [10]

The area of the shaded region = area of semicircle - area of triangle ACB = 11.32 cm².

<h3>What is the Area of a Semi-circle and Triangle?</h3>

Area of a triangle = 1/2(base)(height).

Area of a semi-circle = 1/2(πr²).

m∠ACB is a right triangle based on the central angle theorem. Therefore, ΔACB is a right triangle.

Radius of circle = OC = 4 cm

CB = 4 cm

Diameter AB = 2(4) = 8 cm

Using the Pythagorean theorem, find AC in ΔACB:

AC = √(AB² - CB²)

AC = √(8² - 4²)

AC ≈ 6.9 cm

Area of ΔACB = 1/2(CB)(AC)

Area of ΔACB = 1/2(4)(6.9)

Area of ΔACB ≈ 13.8 cm²

Area of semicircle = 1/2(πr²) = 1/2(π)(4²)

Area of semicircle ≈ 25.12 cm²

Area of the shaded region = area of semicircle - area of triangle ACB = 25.12 - 13.8

Area of the shaded region = 11.32 cm²

Learn more about the area of semicircle and triangle on:

brainly.com/question/14711792

#SPJ1

5 0
3 years ago
6x + 8 - 13x + 10 = 4 - 6x - 11 + 4x
Pavlova-9 [17]

Answer:

5

Step-by-step explanation:

6x+8-13x+10=4-6x-11+4x

-7x+18=-2x-7

    -18       -18

-7x=-2x-25

+2x  +2x

-5x=-25

/-5   /-5

x=5

8 0
4 years ago
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