The proportion of field mice weighing more than 33 grams in the distribution will be about 0.2275
- Mean, μ = 25 grams
- Standard deviation, σ = 4 grams
- Score, X = 33 grams
We need to calculate the P(Z > Zscore)
Recall :
Zscore = (X - μ) ÷ σ
For X > 33 :
Zscore = (33 - 25) ÷ 4 = 2
Therefore, the probability would be expressed as :
P(Z > 2) = 1 - P(Z < 2)
From the normal distribution table :
P(Z < 2) = 0.97725
Therefore,
P(Z > 2) = 1 - 0.97725 = 0.02275
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Exactly 80 liters of 20% are needed.
Let quantity of 20% alcohol solution be added : x liters
Here is the work:
> x*20% + 40 * 50% = (x+40) * 30%
> x*0.2 + 40*0.5 = (x+40)*0.3 ..(converting percentages into decimal)
> 0.2x + 20 = 0.3x + 12
> 20-12 = 0.3x - 0.2x (Rearranging similar terms)
> 8 = 0.1 x
Hence x = 8/0.1
Ans 80 Litres
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