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lorasvet [3.4K]
3 years ago
9

Do you need a contractor to install nest thermostat

Computers and Technology
1 answer:
Natalka [10]3 years ago
5 0

Answer:

Sometimes yes, sometimes you can do it yourself

Explanation:

Installing a Nest thermostat can be done yourself without an electrician in most cases. Nest thermostats are designed to work in homes without a common (“C”) wire. However, there are rare cases a C wire or other power-supply accessory may be required. An electrician is recommended in these rare cases.

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How can you use the Address Book to address an email message? Use the drop-down menus to complete the sentences. 1. Type an emai
Delvig [45]

Answer:

1. AutoCorrect

2. Address book

Explanation:

stan bts ?

5 0
3 years ago
Read 2 more answers
Given three variables, a, b, c, of type double that have already been declared and initialized, write a statement that prints ea
mihalych1998 [28]

Answer:

The statement is written in Java.

  1. System.out.printf("%.5f %.5f %.5f",a,b,c);

Explanation:

Presume that there are three variable a, b and c which have already been declared and initialized with 4.014268319, 14309, 0.00937608 respectively.

To print each of the value with 5 digits to the right of the decimal point, we can use printf() method. We create a format specifier %.5f which is a placeholder of a floating point value. The .5 will specify five digits to the right of the decimal point.

We just create three similar format specifiers ( one for variable a, b, and c, respectively) and include them into printf() method. This will print the output as follows:

4.01427 14309.00000 0.00938  

6 0
3 years ago
4) To run program short cut​
quester [9]

Answer:

Run Dialog

Open it by pressing WinKey+R. In the Run dialog, type the name of a program's .exe file and press Enter to launch it.

Explanation:

Please give me brainlist and follow

6 0
3 years ago
Write a function named print_sum that accepts three numbers as parameters and prints the sum.
OLEGan [10]

Answer:

Complete C++ code along with output and comments for explanation is provided below.

C++ Code with Explanation:

#include <iostream>

using namespace std;

// implement a function named print_sum which takes three input numbers of type int and returns the sum of these three numbers.

int print_sum(int num1, int num2, int num3)

 {

// initialize the variable to hold the value of sum

     int sum;

// add the three numbers and store the result in the variable sum

     sum = num1 + num2 + num3;

// print the sum of three numbers

     cout<<"The sum of three numbers is: "<<sum<<endl;

 }

// driver code starts here

int main()

{

// initialize the three input numbers

   int x,y,z;

// get the three numbers from the user

   cout << "Please enter number 1: "<<endl;

   cin >> x;

   cout << "Please enter number 2: "<<endl;

   cin >> y;

   cout << "Please enter number 3: "<<endl;

   cin >> z;

// call the function print_sum to calculate the sum

   print_sum(x,y,z);

   return 0;

}

Output:

Please enter number 1:

24

Please enter number 2:

13

Please enter number 3:

7

The sum of three numbers is: 44

7 0
3 years ago
A computer has a cache and main memory. 20 ns are required to reference a word that is in the cache. If the word is in main memo
Alecsey [184]

Answer:

T_{average} =12026ns

Explanation:

Given Information:

T_{cache}=20 ns

T_{main}=60ns

T_{disk} =12ms=12,000,000ns

hit_{cache} =0.9

miss_{cache} =1-0.9=0.10

hit_{main} =0.99

miss_{main} =1-0.99=0.01

There are 3 possible cases

1. Location of reference word is in cache

T_{cache}*hit_{cache} =20*0.9=18ns

2. Location of reference word is not in cache but in main memory

(T_{cache}+T_{main})*(miss_{cache}*hit_{main}) =(20+60)*(0.10*0.99)=7.92ns

3. Location of reference word is neither in cache nor in main memory

(T_{cache}+T_{main}+T_{disk})*(miss_{cache}*miss_{main})

(20+60+12,000,000)*(0.10*0.01)=12000.08 ns

The average time required to access a referenced word on this system is simply the sum of above 3 cases

T_{average} =18+7.92+12000.08=12026ns

5 0
3 years ago
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