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alexandr1967 [171]

3 years ago

9

A basketball player scored 24 points by shooting two-point and three-point baskets. If she made a total of ten baskets, how many

of each type did she make?
Pls help

1 answer:

Sati [7]3 years ago

4 0

Six two point shots is 12 points.
of the 21 scored, that leaves nine points, or three 3-point shots. (If my math is right)

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Answer:

Step-by-step explanation:

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Joan gets $1,000 paycheck each month. She saves $50 from each paycheck. What percent of her paycheck does Joan save?

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Answer:

The percentage of paycheck Joan saves is 5% .

Step-by-step explanation:

Given as :

The paycheck that Joan gets each months = x = $1,000

The money that Joan saves from each paycheck = y = $50

Let The percentage of paycheck Joan saves = z%

<u />

<u>Now, According to question</u>

The percentage of paycheck Joan saves = $\dfrac{\textrm money that Joan saves from each paycheck}{\textrm total paycheck money}$ × 100

Or, z = $\dfrac{y}{x}$ × 100

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Or, z = 5%

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3 years ago

Nora uses 2 ft of ribbon to make a bow she has 8 yards of ribbon . how many bows can she make

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4 years ago

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Solve rational exponents x2/3=16

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Step-by-step explanation:

First, we know that 2/3 of something is 16. So, we are going to find 1/3. To do this, we divide 16 by 2 because 2 is the numerator. We get 8 as our answer.

Next, now we have to find the full value. To do this, we need to multiply 8 by 3 to get 3/3 (our full number-answer). When you multiply 8 by 3, you get 24 as your answer.

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Hope this helps!

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3 years ago

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Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

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Substituting the point A(-2,3), we get;

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Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

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Thus, the coordinates of the point B' is (0,-3)

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The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

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