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3 years ago

How do I find the value of WQ

Mathematics

1 answer:

Brut [27]3 years ago

4 0

Answer:

WQ = 2.67 to the nearest hundredth.

Step-by-step explanation:

The area of triangle PQX = 1/2 * PX * QX.

The area of the rectangle = 8 * YX .

But YX = 2 PX so its area = 8 *2PX = 16*PX.

We are given that area of PQX is 1/6 of the area of WXYZ, so we have the equation:-

16 PX = 6* 1/2*PX * QX

16 = 3QX

QX = 16/3 = 5.33

Finally WQ = WX - QX

= 8 - 5.33

= 2.67

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What is the mode for the data set? 59,57,56,50,58,51,54,59,55,52,53 (multiple choice)

jok3333 [9.3K]

The mode for this is 59

Other stuff you may need:
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3 years ago

Read 2 more answers

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

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$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
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So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

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3 years ago

(12 points and brainliest!) A group of armed forces personnel were surveyed. The branch of service was recorded in the chart bel

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Answer:

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Step-by-step explanation:

1. First, find the total number of people who were surveyed.

165+135+60+130+10=500

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3. Last, find out what degree the 12% would take up.

We know that a circle is 360 degrees. To find 12% of 360 degrees, you will do:

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So, the answer is 43.2 degrees

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3 years ago

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lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

Step(i):-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

Null Hypothesis:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

Alternative Hypothesis :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step(ii):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

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2 years ago

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Answer:

well one similarity is that they both cross over zero and one difference is that one is going verticl and one is going up and down

Step-by-step explanation:

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2 years ago