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sergejj [24]
3 years ago
5

a truck weighs 1 ton 1350 pounds the weighs limit for a bridge is given in pounds how many pounds does the truck weigh

Mathematics
2 answers:
topjm [15]3 years ago
3 0
The answer is 3350 pounds

lana66690 [7]3 years ago
3 0
Just divide the two and that's your answer
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A group of friends were working on a student film that had a budget of $900. They used 87% of their budget on costumes. How much
lions [1.4K]

Answer:

They spent $600 on costumes.

Step-by-step explanation:

10% = $800 ÷ 10 = $80

20% = $80 x 2 = $160

 

50% = $800 ÷ 2 = $400

5% = $80 ÷ 2 = $40

400 + 160 + 40 = $600

Hope this helps!

Step-by-step explanation:

6 0
3 years ago
Blair spent 45% of her birthday money on new clothes. What fraction of her money is that equivalent to?
Naddik [55]
Answer: C

Explanation: divide the numerator by the denominator. And then multiply it by 100.
9 divided by 20 which is .45 and when you multiply it by 100 you get 45%
8 0
3 years ago
You are a contractor and charge $45 for a site visit plus an additional $24 per hour for each hour you spend working at the site
tino4ka555 [31]

Answer:

Equation: 810= (90 + 24y)

y = 30 hours

Step-by-step explanation:

Given:

Site visit = $45 per site

cost per hour worked = $24

for <u>each </u>work site, the total amount of money earned

= site visit fee + cost for working

But the question mentions TWO sites, hence there will be two site visits. Therefore for TWO sites, we have to account for TWO site visit fee.

Therefore for TWO sites, the total amount of money earned

= site 1 visit fee + site 2 visit fee + cost for working

= (2 x site visit fee) +  cost for working  ------ Equation 1

We are further given that we worked y hours at the hourly work rate of $24 per hour.

Hence the cost for working

= y hours x hourly rate

= y   x   $24

= $24y   (substituting this into equation 1 above)

for TWO sites, the total amount of money earned

= (2 x site visit fee) +  cost for working

= (2 x $45) +  $24y

= $90 + $24y

= $(90 + 24y)

We are also given that we have to earn $810 for two sites, hence

810 = 90 + 24y    

810 - 90 = 24y

24y = 720

y = 720/24

y = 30 hours

8 0
4 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
Describe at least two similarities between constructing a perpendicular line through a point on a line and constructing a perpen
Vitek1552 [10]

The similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line include:

  • Both methods involve making a 90-degree angle between two lines.
  • The methods determine a point equidistant from two equidistant points on the line.

<h3>What are perpendicular lines?</h3>

Perpendicular lines are defined as two lines that meet or intersect each other at right angles.

In this case, both methods involve making a 90-degree angle between two lines and the methods determine a point equidistant from two equidistant points on the line.

Learn more about perpendicular lines on:

brainly.com/question/7098341

#SPJ1

3 0
2 years ago
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