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3 years ago

What can go into 123 and 1000 evenly

2 answers:

4 0

Nothing can go into 123 and 1000 evenly. 3 can go into 123 evenly but not 1000. And other numbers won't go into 123 evenly.

r-ruslan [8.4K]3 years ago

4 0

Answer:what the guy above this said

Step-by-step explanation:

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Dana buys a plot of land that is 30 yards by 50 yards to build a new house. Dana’s blueprint for the new house shows that the ho

maks197457 [2]

Answer:

Solution: Convert the lot dimensions to feet

35 yards ×3 feet1 yard=105 feet

50 yards ×3 feet1 yard=150 feet

So the area of the entire lot is 105 feet×150 feet=15,750 square feet.

Therefore the percent of the lot NOT covered by Dana's house will be

15,750−160015,750≈0.898≈90%.

Solution: Convert the house area to square yards

Step-by-step explanation:

1 yard=3 feet,

1 square yard=3 feet×3 feet=9 square feet.

Therefore, Dana's house covers

1600 square feet×1 square yard9 square feet≈177.8 square yards.

On the other hand, Dana's lot is 35 yards×50 yards=1,750 yards.

The percentage of Dana's lot NOT covered by her house is:

1,750−177.81,750≈0.898≈90%

7 0

3 years ago

Please Please Please help me in this assignment write a word problem related to finding consecutive integers, the picture is inc

Shkiper50 [21]

Hello,

Shall we begin?

x + 2 ( x + 2 ) = 16
x + 2x + 4 = 16
3x = 16 - 4
3x = 12
x = 12/3
x = 4

<span>Answers: x = 4</span>

4 0

4 years ago

You owe 1200 on your credit card which charges 1.5 per month

Ivahew [28]

40 meses com um custo de 4030 reais por mes espero ter ajudado bjjs

6 0

3 years ago

Use the graphing calculator to graph the quadratic function y = x2 − 5x − 36. Which value is a solution of 0 = x2 − 5x − 36?

Nuetrik [128]

Answer: -4

Step-by-step explanation:

Once you graph it, the solutions are where the graph meets the x axis.

This is at -4 and 9.

6 0

2 years ago

What is the true solution to the equation below?

Marina CMI [18]

Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

$\ln \left(e^{\ln \left(x\right)}\right)+\ln \left(e^{\ln \left(x\right)\cdot \:2}\right)=2\ln \left(8\right)$

$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

$\ln \left(x\right)+\ln \left(x\right)\cdot \:2=2\ln \left(8\right)$

$\mathrm{Add\:similar\:elements:}\:\ln \left(x\right)+2\ln \left(x\right)=3\ln \left(x\right)$

$3\ln \left(x\right)=2\ln \left(8\right)$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3\ln \left(x\right)}{3}=\frac{2\ln \left(8\right)}{3}$

$\ln \left(x\right)=\frac{2\ln \left(8\right)}{3}.....A$

Solving the right side of the equation A.

$\frac{2\ln \left(8\right)}{3}$

$\ln \left(8\right):\quad 3\ln \left(2\right)$

Because

$\ln \left(8\right)$

$\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3$

⇒ $\ln \left(2^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(2^3\right)=3\ln \left(2\right)$

$\frac{2\ln \left(8\right)}{3}=\frac{2\cdot \:3\ln \left(2\right)}{3}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6$

$=\frac{6\ln \left(2\right)}{3}$

$\mathrm{Divide\:the\:numbers:}\:\frac{6}{3}=2$

$=2\ln \left(2\right)$

So, equation A becomes

$\ln \left(x\right)=2\ln \left(2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$=\ln \left(2^2\right)$

$=\ln \left(4\right)$

$\ln \left(x\right)=\ln \left(4\right)$

$\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)$

$x=4$

Therefore, the solution is

$x=4$

6 0

3 years ago

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