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yarga [219]
3 years ago
5

A car covers a distance of 60 km in half an hour . What is he average speed of the car?And with short solution.

Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer: 12

Step-by-step explanation:  If it was 60km in 1 hour it would 6 but since its half an hour just double the 6.

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The perimeter of the trapezoid-shaped window frame is 23.59 feet. Write and solve an equation to find the unknown side length x
krok68 [10]

Answer:

5.62 + 3.65 + 5.62 + x = 23.59

x = 8.7 ft

Step-by-step explanation:

Perimeter of the trapezoid-shaped window = sum of all the sides of the window frame

Thus, the equation to find the unknown side length, x, would be:

✔️5.62 + 3.65 + 5.62 + x = 23.59

Solve for x

14.89 + x = 23.59

Subtract 14.89 from each side

14.89 + x - 14.89 = 23.59 - 14.89

✔️x = 8.7 ft

4 0
3 years ago
How many time can 25 go in 389
iren2701 [21]
15 times is the answer
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3 years ago
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Anyone know how to do parts of complex numbers
Agata [3.3K]

Answer:

Re = 6.2

Im = 37

Step-by-step explanation:

Re is the Real Axis which is the real number in the equation (6.2).

Im is the Imaginary Axis which is the imaginary number in the equation (37)

6 0
3 years ago
Triangle ABC had a perimeter 18 cm
Alex

Step-by-step explanation:

what is the main condition the lengths of the sides of a right-angled triangle have to fulfill ?

Pythagoras !

c² = a² + b²

c is the Hypotenuse (the baseline opposite of the 90 degree angle), a and b are the so-called legs (the sides enclosing the 90 degree angle).

only if there is a combination of the sides, for which the Pythagoras equation is true, do we have a right-angled triangle. otherwise not.

we also know CA = 18 - 7 - 3 = 8 cm

so, let's try

8² = 7² + 3²

64 = 49 + 9 = 58 wrong

7² = 8² + 3²

49 = 64 + 9 = 73 wrong

3² = 8² + 7²

9 = 64 + 49 = 113 wrong

so, there is no combination, where the Pythagoras equation is true, so it is NOT a right-angled triangle.

4 0
3 years ago
Assessment items Diana is constructing a regular hexagon inscribed in a circle. She begins by drawing a line and labeling a poin
andreyandreev [35.5K]

your options are Put the point of the compass on point B and the pencil point on point C. With the compass point still on B, draw two arcs that intersects the circle with center A.

Use a straightedge to join the four points where the circles intersect.

Draw and label the points where the circles with centers A and B intersect and where the circles with centers A and C intersect.

Put the point of the compass on point B and the pencil point on point C. Using this compass width, put the compass point on A and draw another circle.

5 0
4 years ago
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