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ozzi
3 years ago
13

Last year a large trucking company delivered 4.5x10^5 tons of goods with an average value of $22,000 per ton. what was the total

value of the goods delivered? write the answer in scientific notation.
9.9x10^8
9.9x10^11
9.9x10^9
9.9x10^10
Mathematics
1 answer:
Inga [223]3 years ago
4 0
The answer is 9.9x10^8

All you have to do is take the total amount of goods in tons (450,000 tons) and multiply that by 22,000 (the average price of the goods per ton.)
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10(x+12)=15x solve for x with how ?
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Answer:

x = 24

Step-by-step explanation:

10(x+12)=15x  (Given)

10x + 120 = 15x (Distributive property of equality)

-5x = -120 (Subtraction property of equality)

x = 24 (Division property of equality)

7 0
3 years ago
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Three tanks are capable of holding 361,841, and 901 of the greatest vessel winch can be used to fill each one of them on exact n
daser333 [38]

Answer:

Tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

Step-by-step explanation:

Three tanks are capable of holding 361,841,901

To find which tank can be used to fill each one of them an exact number of time, find HCF(361,841,901)

361=19^2\\841=29^2\\901=17(53)

Therefore,

HCF(361,841,901)=1

So, tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

6 0
3 years ago
Meg invested $16,000 in a savings account . If the interest rate is 6% per year, how much will be in the account in 5 years for
Georgia [21]

Answer: $21,581.60

Step-by-step explanation:

Yep

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3 years ago
In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.
muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are m= 1.0\ kg

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

  • Let initial velocity of ball A\ is\ u_1
  • Initial velocity of ball B\ is\ u_2
  • Final velocity of ball A\ is\ v_1
  • Final velocity of ball B\ is\ v_2
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Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

mu_1+mu_2=mv_1+mv_2

We will plug each trial to this equation.

Trial 1

mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3

Trial 2

mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1

Trial 3

mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1

Trial 4

mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

5 0
3 years ago
Help and explain, my teacher did not
Anton [14]

Answer: x=136 degrees

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4 0
3 years ago
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