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kramer
3 years ago
8

Please help me with math please and explain if u explain i will give brainlist also thanks

Mathematics
2 answers:
sasho [114]3 years ago
5 0

Answer:

number 1. is C and number 2. is A

Mekhanik [1.2K]3 years ago
3 0

Answer:

1) 1,2,3

2) 1

Step-by-step explanation:

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Keith has $100 in a savings account at the beginning of the summer. He makes $25 each week at his babysitting job. He wants to h
viktelen [127]

Answer:

100+25x > 350

Step-by-step explanation:

We are given the following in the question:

Keith has $100 in a savings account at the beginning of the summer.

Let x be the number of weeks he works.

He makes $25 each week at his babysitting job.

He wants to earn more than $350 dollars during summer.

Total money earned by job = 25x

His total money in account should be more than 350$.

We can write this with the help of inequality:

100+25x > 350

The following inequality represents the given situation.

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3 years ago
This graph represents the demand for health supplements in Oklahoma. Match each section of the function to the description of ho
nasty-shy [4]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The original line has the equation of y=-2x+8
enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is y = \frac{1}{2}x - 4

<h3><u>Solution:</u></h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute m = \frac{1}{2} and (x, y) = (6, -1) in eqn 1

-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4

<em><u>Thus the required equation of line is:</u></em>

Substitute "c" = -4 and m = \frac{1}{2} in eqn 1

y = \frac{1}{2}x - 4

Thus the equation of line perpendicular to original line is found

7 0
3 years ago
4+ y = 10<br> What is the answer and how do I solve it
julia-pushkina [17]

Answer:

y=6

Step-by-step explanation:

4+y=10

-4     -4

   y=6

just subtract 4 from both sides

8 0
3 years ago
What is the y-intercept of the quadratic y=-2x^2-4x-5 ?<br> (-5,0)<br> (0,-2)<br> (-1,3)<br> (0,-5)
stepan [7]
Y - intercept is f(0) then (0; m)

We have:

y=-2x^2-4x-5\to f(0)=-2(0)^2-4(0)-5=-5

Answer: (0; -5)
5 0
3 years ago
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