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2 years ago

PLEASE HURYY

Mathematics

1 answer:

anygoal [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Use the fact that C + 118 = 180 Subtract 118 from both sides

C + 118 - 118 = 180 - 118

C = 62

C + 57 = B C and A are remote interior angles. They equal the exterior angles that are not supplementary to B.

62 + 57 = B

B = 119

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I need to find two equivalent fractions for each whole number. the whole numbers are 4, 5, 3, and 6.

Archy [21]

For the #4 - 8/2 & 16/4
For the #5 - 10/2 & 25/5
For the #3 - 6/2 & 9/3
For the #6 - 12/6 & 36/6

I think these are right .. Hope this helps. (:

6 0

2 years ago

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0

2 years ago

Emma says the GCF of 16 and 12 is 48. Her friend grace says the answer is right. Who is right? Explain help me plz

Lilit [14]

The GCF is only 12 because 16 can't multiply a number that gives you 48 only 12.

6 0

2 years ago

PLEASE PLEASE HELP what is f(1)

Dafna1 [17]

Answer:

Step-by-step explanation:

f(1) means what is the value when x=1. y is at 5.

4 0

2 years ago

Read 2 more answers

What is the answer to page 156-157 on chapter 4 proportions relationship.

timurjin [86]

Proportional relationships: A relationship between two equal ratios. Proportions are the comparison of two equal ratios. Therefore, proportionalrelationships are relationships between two equal ratios. For example, oranges are sold in a bag of 5 for $2. The ratio of oranges to their cost is 5:2 or.In mathematics, two variables are proportional if a change in one is always accompanied by a change in the other, and if the changes are always related by use of a constant multiplier. The constant is called the coefficient of proportionality or proportionality constant.

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2 years ago