All categories

2 years ago

1. 7/18 * 1 ⅐ + 2/3. 2. 3x + 1 ⅐ = 2

Mathematics

1 answer:

anzhelika [568]2 years ago

7 0

Answer:

Step-by-step explanation:

for first one's answer visit;

https://answers.everydaycalculation.com/subtract-fractions/2-3-minus-7-18

for sencond one;

3x=2+1

3x=3

x=1

for more info visit;

https://www.cymath.com/answer?q=3x-1%3D2

You might be interested in

3 (x-5)?????????????

Yakvenalex [24]

3(x-5), using the distributive property, we get 3x - 15

6 0

3 years ago

Read 2 more answers

Solve for k: 4 + k/6 = x times 4

loris [4]

Here is your answer....

3 0

3 years ago

What is 2y(x+4x-2x^2-8) completely factored

cluponka [151]

Answer:

$10yx-4yx^{2} -16y$

Step-by-step explanation:

7 0

3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago

What is an equation of the line that passes through the points (-6, -5) and (-3,0)? Put your answer in fully reduced form.

MrMuchimi

Answer:

y = 5/3x +5

Step-by-step explanation:

The two-point form of the equation of a line is useful here.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (0 -(-5))/(-3 -(-6))(x -(-6)) -5

y = 5/3(x +6) -5

y = 5/3x +5 . . . . slope-intercept form

5x -3y = -15 . . . .standard form

_____

There is no "fully reduced" form of the equation of a line. There are slope-intercept form, point-slope form, two-point form, standard form, general form, intercept form, and some others. We assume that "fully reduced" applies to any fractions in the equation. The "slope-intercept" form has a fraction, so perhaps that's the form that is required.

6 0

3 years ago

1. 7/18 * 1 ⅐ + 2/3. 2. 3x + 1 ⅐ = 2​

1. 7/18 * 1 ⅐ + 2/3. 2. 3x + 1 ⅐ = 2