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Nutka1998 [239]
3 years ago
6

What is the variable equal to? 6x = 24 x = 5 x = 4 x = 144 x = 3

Mathematics
2 answers:
almond37 [142]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

divide 6x and 24 with 6 you get x as 4

olganol [36]3 years ago
3 0

Answer:

x=4

Step-by-step explanation:

Divide both sides by 6.

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E probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the nu
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The probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the null hypothesis is true is the definition of "P-Value."

<h3>What is null hypothesis?</h3>

A null hypothesis is a sort of statistical hypothesis which asserts that there is no statistical significance in a particular set of observations.

Using sample data, hypothesis testing is performed to determine the believability of a theory. It really is expressed as H0 and is also known to simply as "null."

Some key features regarding null hypothesis are-

  • A null hypothesis is a statistical conjecture that claims there is no variation between particular qualities of a population and data-generating process.
  • The alternate hypothesis asserts the existence of a distinction.
  • Hypothesis testing allows you to reject the null hypothesis with a particular level of confidence.
  • If the null hypothesis can be rejected, it lends support to the alternative hypothesis.
  • The notion of falsity in science is founded on null hypothesis testing.

To know more about null hypothesis, here

brainly.com/question/14016208

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2 years ago
a feature is common to all exponential functions of the form F(x)=b^x is that they have a common horizontal asymptotic at the
Lena [83]
The asymptote is at the x-axis, when y=0.
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3 years ago
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Show how you can make a ten to find the sum. 8+5=__10+__=__
klio [65]
8 + 5 = 13
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Can a random variable have infinite mean
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6 0
3 years ago
Find the solution to dy/dt = 7 y<br><br> satisfying<br> y(9) = 5
AVprozaik [17]
\rm \dfrac{dy}{dt}=7y,\qquad\qquad\qquad y(9)=5

I'm not sure what methods you've learned up to this point but one option is to apply separation of variables:

\rm \dfrac{dy}{y}=7dt

and then integrate from there,

\rm ln|y|=7t+c

exponentiate to isolate y,

\rm |y|=e^{7t+c}

Apply exponent rule,

\rm |y|=e^c e^{7t}

rename this e^c as some new constant, perhaps A,

\rm \pm y=A e^{7t}\qquad\qquad A>0

This A can only be positive, non-zero, but absorbing the plus/minus fixes that restriction,

\rm y=A e^{7t}\qquad\qquad A\ne0

Use your initial information to solve for this unknown value A,

\rm y(9)=A e^{7\cdot9}=5

solving for A, dividing by the exponential,

\rm A=5e^{-63}

So we get a final result of

\rm y(t)=5e^{-63}e^{7t}

apply exponent rule again to get a better looking answer, and factor,

\rm y(t)=5e^{7(t-9)}

Lemme know if too confusing.
3 0
3 years ago
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