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2 years ago

Solve the polynomial inequality and graph the

Mathematics

1 answer:

valkas [14]2 years ago

6 0

Answer:

-6 < x < 3/4

Step-by-step explanation:

Hope this helps <333

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If A and B are mutually exclusive events with P(A)= 0.3 and P(B)= 0.5, then P(A and B)=

arsen [322]

Answer:

$P (A\ and\ B) = 0$

Step-by-step explanation:

By definition if two events are mutually exclusive then they are disjoint events, that is, they can not occur at the same time.

In general terms we say that events are mutually exclusive, then:

$P (A\ and\ B) = 0$

In this case we have that

$P(A)= 0.3\\\\P(B)= 0.5$

But A and B are mutually exclusive events, then $P (A\ and\ B) = 0$

4 0

2 years ago

Using radians, find the amplitude and period of each function.

ELEN [110]

Go to Math Papa that'll give you the answers with the work shown and explanations.

6 0

2 years ago

2, -6, 18, __, 162, __, ...

Semmy [17]

Answer:

-54, 162, -486

Step-by-step explanation:

You multiply the number in front by -3.

2*-3=-6

-6*-3=18

18*-3=-54

-54*-3=162

162*-3=-486

-Please mark as brainliest!-

-Hope this helps!-

-Good Luck!-

7 0

3 years ago

Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t

Elden [556K]

Answer: a) $\bold{\dfrac{3}{16}}$ b) $\bold{\dfrac{1}{36}}$

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

2) Even, Even, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

3) Odd, Odd, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

<em>Order doesn't matter</em>

Add them up to get your answer: $\dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}$

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

$\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}$

3 0

2 years ago

What is the residuals for this scatterplot? I WILL MARK BRAINLIEST!

vazorg [7]

wait do what? im confused

4 0

2 years ago