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ohaa [14]
4 years ago
9

140/100 simplified as a fraction

Mathematics
2 answers:
Jet001 [13]4 years ago
4 0

Answer:7/5

Step-by-step explanation:

140/100 = 7/5 = 1 2/5

Mumz [18]4 years ago
4 0

Answer:7/5

Step-by-step explanation:

140/100=14/10=7/5

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An art gallery wants to display 4 pieces of art in the front window. If there are 8 pieces to choose from, how many distinct dis
Viktor [21]

Answer:

D-70

Step-by-step explanation:

It is a combination C(8,4)

5 0
3 years ago
Help⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️​
s344n2d4d5 [400]

Answer:

Get a calculator a graphing calculator and insert each one of those in it

4 0
3 years ago
For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
4 years ago
Can somebody help me solve for x?
Dahasolnce [82]

Let y = the distance between the top left corner and the bottom right corner

y^2 = 24^2 + 15^2

y^2 = 801

y = 3 * sqrt(89)

Now we can find x.

12^2 + x^2 = (3 * sqrt(89))^2

x^2 = 657

x = 3 * sqrt(73) or 25.63

7 0
3 years ago
An angle measures 114° less than the measure of its supplementary angle. What is the measure of each angle?
dezoksy [38]

Answer:

66°

Step-by-step explanation:

x+114°=180°

x+114°-114°=180°-114°

x=66°

3 0
3 years ago
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