Answer:
Justin is 23 years old, and Aimee is 42 years old.
Step-by-step explanation:
Let Marcella's age be represented by x, and Justin's age by t.
Given that Justin is 2 years older than one third Marcella's age.
t = 
x + 2
t = 
+ 2 ........... 1
Also, Aimee is four years younger than 2 times Justin's age.
Aimee = 2 x t - 4
Aimee = 2t - 4 .......... 2
But, Marcella's age is 63 years, so that from equation 1;
Justin's age = + 2
= 
+ 2
= 21 + 2
= 23
Justin is 23 years.
From equation 2,
Aimee = 2 x 23 - 4
= 46 - 4
= 42
Aimee is 42 years.
Therefore,
Marcella is 63 years old, Justin is 23 years old, and Aimee is 42 years old.
E^x = 1 + x + x² / 2 + x³/ 3! + x^4 / 4! + .....
= (1 + x + x²/2 ) + x³ [ 1/6 + x /4! + x² / 5! + .... ]
Error = e^x - (1+ x + x² ) = x³ [ 1/6 + x /4! + x² / 5! + .... ]
x / 4! < x / 6 x² / 5! < x² / 6 and so on
So if we replace all factorials by 1/6 ..
error < x² [ 1/6 + x/6 + x²/6 + ... ]
< x² / 6 [ 1 + x + x² ..... ]
< x² / 6 * 1 / (1 -x) = x² / 6 (1-x) if x < 1
maximum error = x² /6(1-x) occurs at 0.4 or -0.4 in the given interval.
= 0.0444444
m <3 + 138 =190
so m<3 = 180 -138 = 42
r ans t are parallel so m<3 = m<6 then m<6 = 42
answer <span>C.42</span>
Answer:
The answer is 4 zeros
Step-by-step explanation:
(6×5)×10³
30×1000=30000
Therefore 4 zeros in 30000
Answer:8
Step-by-step explanation:
I'm smort
