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Alecsey [184]
3 years ago
5

Help leave in simplest radical form

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Hi. Hope it has helped you.

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Plz plz plz plz plz help me I don't really understand
Shkiper50 [21]
The correct answer to this equation is G 1 year and 6 months. Hope this helped.
4 0
4 years ago
What is the simplest form for 28 out of 32
Oksi-84 [34.3K]

Answer:

Ans = 7/8

Step-by-step explanation:

28 out of 32

= 28/32

Dividing through by 4

= 28/4 / 32/4

= 7/8

5 0
4 years ago
The revenue for a company producing widgets is given by y = -20x2 - 50x + 200, where x is the price in dollars for each widget.
lisov135 [29]

Answer:

The  price is   x =  $2.779

Step-by-step explanation:

From the question we are told that

  The  revenue is  y = - 20x^2  - 50 x + 200

   The cost of production is  y = 30 x - 10

Generally at break even point the cost of production is equal to the  revenue

So

      -20x^2 -50x + 200 =  30x-10

=>   20x^2 +20 -210 = 0

Using the quadratic formula to solve this equation we have that

       x =  $2.779

     

6 0
3 years ago
Read 2 more answers
Answer get brainliest
lisov135 [29]
I would say question A)B, B)D and C)D. I’m not sure about C, but that is my best estimate.
8 0
3 years ago
Read 2 more answers
Prove that:
andre [41]

<u>Explanation:</u>

On taking LHS

Cos[(3π/2)+θ]Cos(2π+θ)[Cot{(3π/2)-θ}+Cot(2π+θ)]

We know that

π = 180°

2π = 2×180° = 360°

3π/2 = (3×180°)/2 = 540°/2 = 270°

Now

LHS becomes

Cos(270°+θ)Cos(360°+θ)[Cot(270°-θ)+Cot(360°+θ)]

We know that

Cos (270°+θ) = Sin θ

Cos (360°+θ) = Cos θ

Cot (270°-θ) = Tan θ

Cot (360°+θ) = Cot θ

→ Sin θ Cos θ [Tan θ + Cot θ]

→ Sinθ Cosθ[(Sinθ/Cosθ)+(Cosθ/Sinθ)]

→ Sinθ Cosθ[(Sin²θ+Cos²θ)/(SinθCosθ)]

→ Sin θ Cos θ [1/(Sin θ Cos θ)]

Since Sin²θ+Cos²θ = 1

→ (Sin θ Cos θ)/(Sin θ Cos θ)

→ 1

→ RHS

→ LHS = RHS

<u>Hence, Proved.</u>

Here are the formulae that I have used:

→ π = 180°

→ Cos (270°+θ) = Sin θ

→ Cos (360°+θ) = Cos θ

→ Cot (270°-θ) = Tan θ

→ Cot (360°+θ) = Cot θ

Here are the Trigonometric Identities that I have used:

→ Sin²θ+Cos²θ = 1

Hope this helps!!

8 0
3 years ago
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