The probability that the first student is a girl is 5/10.
The probability of the second selection being a boy is 5/9.
(since the first selection was a girl, there are 9 students left)
The probability that the third student is a girl is 4/8
(there are 4 girls left after one was selected, and 8 students left in total, after the second selection.
The probability is (5/10)(5/9)(4/8)=0.139
Answer: 0.139
√-80 can be factored out, to see which factors can be square rooted. A pair of factors would be 16 and -5, so that would be 4√-5. But, negative numbers cannot be inside a square root. So, √-1 is the same thing as <em>i</em>, or <u>imaginary number</u>. So, the expression equivalent to √-80 is 4<em>i</em>√5.
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Ok so the lines with two triangles are parralel to eachother. The lines with one are parallel to eachother.
The angle of 109° and angle of z° equal eachother. Z=109°
Since 109°, 33° and y° form a triangle, the sum of the angles will equal 180. Add 109 and 33 to get 142. Subtract 142 from 180 to get y°=38°.
Since z=109, this means that the triangle is congruent with the other. Since the congruent triangles are in a rhombus, then the angles are flipped. Thus, angle x =33°.
z=109°
y=38°
x=33°
The answer is 10mm, I answered this in a previous question.
Answer:
9,765 cm
Step-by-step explanation:
We'll solve out the measurements for triangle ABC then it will be easy to figure out x
For triangle ABC, we have
Angle B = 90 degrees.
Angle A (CAB) = 38 degrees (the angle CAD is 19 and is said to be half of CAB, since the line AD is a bisector).
Angle C = 180 - 90 - 38 = 52 degrees.
To find the measurement of the BC line, which we label a, we know that
So, we can isolate the a to get:
Now we know the segment BC is 19.53 cm.
And we know that segments CD and DB are equal, since AD is a bisector, cutting the CAB angle in half.
So, CD is half of BC.... so 19.53 / 2 = 9.765 cm
