Answer:
here's the solution : -
=》2x - 3y = -29
=》x + 6y = 23
=》x = 23 - 6y
now, plugging the value of x in equation 1, we get : -
=》2x - 3y = -29
=》2 (23 - 6y) - 3y = - 29
=》46 - 12y - 3y = -29
=》-15y = -29 - 46
=》y = -75 ÷ -15
=》y = 5
now, plugging the value of y as 5 in equation 2
=》x + 6y = 23
=》x + (6 × 5.2) = 23
=》x = 23 - 30
=》x = - 7
Given:
The function is

To find:
The asymptotes and zero of the function.
Solution:
We have,

For zeroes, f(x)=0.



Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.


Taking square root on both sides, we get


So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Answer:
c
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given:


Substitution can be used to find the value of
:




Hope this helps :)
Answer:
b. reflection
Step-by-step explanation:
just took the test