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3 years ago

What do all rational numbers have in common?

Mathematics

1 answer:

NISA [10]3 years ago

5 0

They can be expressed as fractions

they have positive values and can be expressed as terminating decimals.

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A sporting goods store sells right-handed and left-handed baseball gloves. In one month, 12 gloves were sold for a total revenue

stepladder [879]

Answer:

$9$ right-handed gloves and $3$ left-handed gloves were sold.

Step-by-step explanation:

Given: In one month, $12$ gloves were sold for a total revenue of $\$561$ .

right-handed gloves cost $\$45$ and left-handed gloves cost $\$52$ .

To find: How much of each type of gloves did they sell?

Solution: Let they sell $x$ right-handed gloves, and $y$ left-handed gloves.

Now, cost of each right-handed gloves $=\$45$

cost of each left-handed gloves $=\$52$

Total revenue $=\$561$

So, we get

$45x+52y=561\:\:\:...(i)$

Also, in a month $12$ gloves were sold.

So, we get

$x+y=12\:\:\:...(ii)$

Now, from $(ii)$ we get, $x=12-y$ .

Putting $x=12-y$ in equation $(i)$ , we get

$45(12-y)+52y=561$

$\implies 540-45y+52y=561$

$\implies7y=561-540$

$\implies7y=21$

$\implies y=\frac{21}{7}$

$\implies y=3$

Now, putting $y=3$ in equation $(ii)$ , we get

$x+3=12$

$\implies x=12-3$

$\implies x=9$

Hence, $9$ right-handed gloves and $3$ left-handed gloves were sold.

7 0

3 years ago

Complete the square to transform the quadratic equation into the form (x – p)2 = q.

ryzh [129]

The transformed equation is:

$(x-3)^2 = 23$

Step-by-step explanation:

We have to convert the equation in the form

$(x-p)^2 = q$

Given equation is:

$x^2-6x-8 = 6$

Adding 8 on both sides

$x^2-6x-8+8 = 6+8\\x^2-6x = 14$

In the given equation

a = x

b= ?

So,

$2.x.b = 6x\\b =\frac{6x}{2x}\\b = 3\\$

So 3^2 will be added on both sides

$(x)^2-6x+ (3) = 14+ (3)^2\\(x-3)^2 = 14+9\\(x-3)^2 = 23$

Hence,

The transformed equation is:

$(x-3)^2 = 23$

Keywords: Quadratic equation, transformation

Learn more about quadratic equation at:

#LearnwithBrainly

7 0

3 years ago

Price of one CD after February discount $

Ksju [112]

Answer:

vssguudgebseisiehjejsieheusssushsbddjdhfbbfjfjfnfnfnfnfnnfjfngjfjfjfjfjfjfjfjf

6 0

2 years ago

Explain Steps. Do not answer. #10 and 11 Questions are in the Picture

svet-max [94.6K]

Answer:

Step-by-step explanation:

For problem 10:

1. AE/ED=AC/CB (Since triangle ABC is similar to triangle ADE, we can determine that the ratio of AE to ED is equal to the ratio of AC to CB)

2. AE/ED=(AE+EC)/CB (Rewrite AC as the sum of the lengths forming it; This is sometimes referred to as the Partition Postulate)

3. 9/x=(9+6)/10 (Substitute the given values into this equation)

4. x=6 (Use algebra to solve for x)

For problem 11:

1. AG/AB=AE/AD (Use the same strategy as step one in problem 10, since the rectangles are similar we can create this equation)

2. AG/(AG+GB)=AE/(AE+ED) (Rewrite sides as the some of their parts)

3. 14/(14+7)=18/(18+x) (Substitute given values)

4. x=9 (Solve for x)

lmk if there are mistakes in my explanation, hope this helps :)

8 0

3 years ago

The base of a solid is the region in the first quadrant between the graph of y=x2 and the x -axis for 0≤x≤1 . For the solid, eac

nata0808 [166]

Answer:

The volume of the solid is π/40 cubic units.

Step-by-step explanation:

Please refer to the graph below.

Recall that the area of a semi-circle is given by:

$\displaystyle A=\frac{1}{2}\pi r^2$

The volume of the solid will be the integral from x = 0 to x = 1 of area A. Since the diameter is given by y, then the radius is y/2. Hence, the volume of the solid is:

$\displaystyle V=\int_0^1\frac{1}{2}\pi \left(\frac{y}{2}\right)^2\, dx$

Substitute:

$\displaystyle V=\frac{1}{2}\pi\int_0^1\left(\frac{x^2}{2}\right)^2\, dx$

Simplify:

$\displaystyle V=\frac{1}{2}\pi \int_0^1\frac{x^4}{4}\, dx$

Integrate:

$\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]$

Evaluate:

$\displaystyle V=\frac{\pi}{40}\left((1)^5-\left(0\right)^5\right)=\frac{\pi}{40}\text{ units}^3$

The volume of the solid is π/40 cubic units.

4 0

3 years ago