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svlad2 [7]
3 years ago
7

(look at image) can i get help on this problem

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

where is the image??? u should paste the image tooo.

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In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale. For m
Mademuasel [1]

Angle AOC = 46°   Find angle BPO

We have congruent right triangles PAO and PBO, right angles A and B.

So AOC=BOC=46 degrees,

PBO is a right angle so BPO is complementary to BOC, so 42 degrees

Answer: 42 degrees

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2 years ago
−4 2/5 ÷ (−5)<br> divide<br> a) −22/25<br><br> b) −8/25<br><br> c) 8/25<br><br> d) 22/25
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Answer:

the answer to your question is 22/25 , hope this helps :)

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2 years ago
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Wes wants to buy 3 pepper plants from the garden center. The regular price of a pepper plant
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The sale price of 3 pepper plants after a 20% discount is $3

The regular price of one pepper plant is $5 if Wes wants to buy 3 pepper plants 5x3 is 15 and since he can use a 20% off coupon on the pepper plants. 20% of 15 is 3 meaning the sale price for 3 pepper plants after using the 20% discount coupon is $3.
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3 years ago
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Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

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3 years ago
Evaluate the following expression 5^-2/5^0
Ray Of Light [21]

Answer:

Step-by-step explanation:

1/25

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