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2 years ago

Evaluate and answer in standard form:3^3

Mathematics

2 answers:

lisabon 2012 [21]2 years ago

8 0

Answer:

The answer is 27

Step-by-step explanation:

all you do is raise 3 to the third power.

sweet [91]2 years ago

6 0

Evaluate and answer in standard form:
3^3 = 27

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The coordinates of point A on a grid are (−1, 6). Point A is reflected across the y-axis to obtain point B. The coordinates of p

elena55 [62]

When you reflect across the y axis the y coordinate stays the same and the x coorrdinate changes sign so x = -1 goes to x = 1

Answer point B is (1,6)

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3 years ago

Expand and simplify (2x2 + 3)(4x + 5) - 8x(x - 2)

Bezzdna [24]

I think the answer is 2x+12

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3 years ago

What is the equivalent decimal for 27/32?

balandron [24]

Answer is
0.84375 :)
have a good dayy

7 0

3 years ago

Read 2 more answers

3,053/2,8 Alguien me ayuda porfavor? Pero con el proceso porfa

PtichkaEL [24]

Answer:

1.09

Step-by-step explanation:

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2 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

Evaluate and answer in standard form:3^3​

Evaluate and answer in standard form:3^3