Answer:
A. 78
Step-by-step explanation:
Given image can be re-drawn as (see the attachment)
Now, we need to calculate Area I and Area II
So Area I will have length as
.
And width as ![6\ inches](https://tex.z-dn.net/?f=6%5C%20inches)
Area I
![=length\times width\\=11\times6=66\ inch^2](https://tex.z-dn.net/?f=%3Dlength%5Ctimes%20width%5C%5C%3D11%5Ctimes6%3D66%5C%20inch%5E2)
Also, Area II will have length a ![10-6=4\ inches](https://tex.z-dn.net/?f=10-6%3D4%5C%20inches)
And width as ![3\ inches](https://tex.z-dn.net/?f=3%5C%20inches)
Area II
![=length\times width\\=4\times3=12\ inch^2](https://tex.z-dn.net/?f=%3Dlength%5Ctimes%20width%5C%5C%3D4%5Ctimes3%3D12%5C%20inch%5E2)
Total area of the diagram would be sum of Area I and Area II
So, ![66+12= 78\ inch^2](https://tex.z-dn.net/?f=66%2B12%3D%2078%5C%20inch%5E2)
Answer:
128 or 4,096
Step-by-step explanation:
If its 64 x 2 then 128 or if you are implying 64, to the power of two, (64x64) then your answer is 4,096.
Perimeter of rectangular figure is given by:
Perimeter = 2( l+ w)...............(1)
where l and w are length and width of rectangle.
We are given perimeter = 454 yards......................(2)
We are also given length is 5 yards less than triple the width.
So we have length = 3w-5....................(3)
Plugging the values of P and l from (2) and (3) in (1)
![454 = 2( w + 3w-5)](https://tex.z-dn.net/?f=%20454%20%3D%202%28%20w%20%2B%203w-5%29%20)
![454 = 2( 4w-5)](https://tex.z-dn.net/?f=%20454%20%3D%202%28%204w-5%29%20)
dividing both sides by 2 ,
![227= 4w-5](https://tex.z-dn.net/?f=%20227%3D%204w-5%20)
adding 5 on the left side,
![232= 4w](https://tex.z-dn.net/?f=%20232%3D%204w%20)
dividing both sides by 4
w=58
Plugging this value in equation (3) to get length,
![l=3w-5 = 3(58) -5= 169](https://tex.z-dn.net/?f=%20l%3D3w-5%20%3D%203%2858%29%20-5%3D%20169%20)
Answer:
Length is 169 yards and width is 58 yards.
The answer is the 3rd question