Question

Write the point-slope form of the equation for a line that passes through (–1, 4) with a slope of 2.

Answer 1

Point slope is a really easy form for linear equations. It lets you plug in the numbers from a cordinate that the line passes through on the graph and the slope directly. Here is the point slope equation:

$y(2) - y(1) = m(x(2) - x(1)$

(The (2) and (1) next to the x's and y's are suposed to be underneath them. There is also supposed to be an extra parentheses at the end.)

You would replace y(1) with the y value, x(1) with the x value, and m with the slope. For example, if you have a line that crosses through the point (6, 10) with a slope of 3, this is how you would write the equation of the line in point slope form:

$y - 10 = 3(x - 6)$

Now, for this problem, we have the point (1, 4) with a slope of 2. This is the point slope form for the given point and slope:

$y - 4 = 2(x - 1)$

The values of y1 and x1 are the values we plugged into this equation, 4 and 1.

Answer 2

Answer:

y-4 = 2(x+1) is point-slope form of the equation for line that passes through (-1,4) with slope 2.

Step-by-step explanation:

We have given that

Let (x₁,y₁) = (-1,4) and slope= m = 2

We have to find the point-slope form of the equation for a line that passes through (-1,4) with slope  equal to 2.

y-y₁ = m(x-x₁) is point -slope form of the equation of line that passes through (x₁,y₁) with slope m.

The value of x₁ is -1 and the value of y₁ is 4.

Putting values in given formula, we have

y-(4) = 2(x-(-1))

y-4 = 2(x+1) is point-slope form of the equation for line that passes through (-1,4) with slope 2.