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Pie
4 years ago
11

Simplify expression 2 (6)+7+8/3

Mathematics
1 answer:
lutik1710 [3]4 years ago
7 0
6+7+8/3

8/3 = 2 2/3

2 2/3 + 7 + 8 = 17 2/3

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Write in slope intercept form the equation of a line that has a slope of -5 and passes through point -2,-6
mafiozo [28]
y = mx + n

m slope
n y-intercept

for:
m = -5
x = -2
y = -6

-6 = -5*-2 + n

find n and insert it  into the first equation
6 0
3 years ago
The Lateral Area of a cylinder is 8II square feet and its height is 4 ft. Find the radius,
vodka [1.7K]

9514 1404 393

Answer:

  C.  1

Step-by-step explanation:

The lateral area is given by the formula ...

  LA = 2πrh

Filling in the given values, you have ...

  8π = 2π·r·4

  1 = r . . . . . . . . divide by the coefficient of r

The radius of the cylinder is 1 foot.

3 0
3 years ago
The endpoints of jk are j(–25, 10) and k(5, –20). what is the y-coordinate of point l, which divides jk into a 7:3 ratio
Trava [24]
The correct answer for this question is this one: <span>(-4, -11)
</span>In order to solve this,

Let k1 = 7/10 = fraction of the first part
Let k2 = 3/10 = fraction of the second part

Then, use solve for x and y

x = (k1(x2) +k2(x1)) / (k1+k2)
y = (k1(y2) +k2(y1)) / (k1+k2)

x = (7/10 * 5 + 3/10 * -25) / (7/10 + 3/10 )
<span>x = -8 / 2
x = -4

y = (7/10 * -25 + 3/10 * 10) / (7/10 + 3/10)
y = -14 + 3
y = -11

Hope this helps answer your question. Have a nice day!</span>
4 0
4 years ago
Read 2 more answers
Pllllllllllz help number 17
Monica [59]

I will help but I’m dumb sorry

8 0
3 years ago
Function f(z)=2z-(3+i)
Archy [21]
F(z) = 2z - (3+i)

1) second interate for z0 = i

first iterate = f(z0) = f(i) = 2i - 3 - i = i - 3 = z1
second iterate = f(z1) = f(i-3) = 2(i-3) - 3 - i = 2i - 6 - 3 - i = i - 9

2) third iterate for z0= 3 - i

first iterate = f(z0) = f(3 - i) = 2(3-i) - (3+i) = 6 -2i -3 - i =3 - 3i = z1
second iterate = f(z1) = f(3 -3i) = 2(3-3i) - (3+i) = 6 - 6i -3 -i = 3 - 7i = z2
third iterate = f(z2) = f(3 - 7i) = 2 (3-7i) - (3+i) = 6 - 14i - 3 - i = 3 -15i = z3.

3) first iterate for z0=0.5+i

first iterate = f(z0) = f(0.5 +i) = 2(0.5+i) - (3+i) = 1 +2i - 3 - i = - 2 + i = z1

4) third iterate for z0=-2-5i

first iterate = f(z0) = 2(- 2 - 5i) - (3 + i) = - 4 - 10i - 3 - i = -7 - 11i = z1
second iterate = f(z1) = 2( - 7 - 11i) - (3+i) = -14 - 22i - 3 - i = -17 -23i = z2
third iterate = f(z2) = 2(-17-23i) -(3+i) = -34 - 46i -3 - i = -37 - 47i = z3
8 0
3 years ago
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