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3 years ago

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

1 answer:

5 0

Answer by JKismyhusbandbae: A bar graph because they are used a lot to compare the sizes of categories and it would show the countries different populations telephones per every 1000 people.

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A child walks due east on the deck of a ship at 3 miles perhour.

VladimirAG [237]

Answer:

16.28 mph ; 79.38°

Step-by-step explanation:

Given the following :

Speed of child due east = 3mph

Speed of ship due North = 16mph

Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus

Relative Speed = Sqrt(3² + 16²)

Relative Speed = sqrt(9 + 256)

= sqrt(265)

= 16.2788 mph

= 16.28 mph

From trigonometry ;

Tanθ = opposite / Adjacent

Tanθ = (16 / 3)

Tanθ = 5.333

θ = tan^-1(5.333)

θ = 79.379°

θ = 79.38°

6 0

3 years ago

Determine whether quadrilateral ABCD is a rhombus, a rectangle, a square, a parallelogram, or none. List all that apply. Explain

svlad2 [7]

Answer:

ABCD is a rhombus, and a parallelogram

==================================

<h3>Given </h3>

Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)

First, plot the points (see attached picture).

Then, connect all the points.

Opposite sides are parallel,
Diagonals are perpendicular.

From our observation the figure is rhombus.

Let's confirm it with the following.

1) Find midpoints of diagonals and compare.

AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2

The midpoint of both diagonals is same (- 2, 2).

2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.

m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3

m(AC) × m(BD) = 3/4 * (- 4/3) = - 1

<u>Confirmed.</u>

So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.

5 0

10 months ago

Mary must choose a new password where the first and last choices are possibly repeated lowercase letters; the second and third

Salsk061 [2.6K]

The number of ways she can choose a password is 3986236800

<h3>In how many ways can she choose a password?</h3>

The given parameters and the possible selection of characters are:

First and last choices are possibly repeated lowercase letters;

There are 26 lower characters.

Since the characters can be repeated, then we have

First = 26

Last = 26

The second and third positions must be distinct uppercase letters

There are 26 upper characters.

Since the characters are distinct, then we have

Second = 26

Third = 25

The fourth position must be a # , $, or & symbol;

So, we have

Fourth = 3

The next four positions are distinct nonzero digits.

There are 9 nonzero digits.

Since the digits are distinct, then we have

Next = 9, 8, 7, 6

The number of ways she can choose a password is

Ways = First * Second * Third * Fourth * Next * Last

So, we have

Ways = 26 * 26 * 25 * 3 * 9 * 8 * 7 * 6 * 26

Evaluate the product

Ways = 3986236800

Hence, the number of ways she can choose a password is 3986236800