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AlexFokin [52]
3 years ago
14

Multiply (x^2-5x+1)(4x-3x^2)

Mathematics
2 answers:
aleksley [76]3 years ago
6 0

x= 6 is the answer

Step-by-step explanation:

hope it helps

Andreas93 [3]3 years ago
6 0

Answer:

 -x • (x2 - 5x + 1) • (3x - 4)

Step-by-step explanation:

STEP

1: Equation at the end of step 1

 (((x2) -  5x) +  1) • (4x -  3x2)

STEP2:STEP

2:Pulling out like terms

 Pull out like factors :

4x - 3x2  =   -x • (3x - 4)

Trying to factor by splitting the middle term

 Factoring  x2 - 5x + 1

The first term is,  x2  its coefficient is  1 .

The middle term is,  -5x  its coefficient is  -5 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   1 • 1 = 1

Step-2 : Find two factors of  1  whose sum equals the coefficient of the middle term, which is   -5 .

     -1    +    -1    =    -2

     1    +    1    =    2

Observation : No two such factors can be found !!

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Answer:

4.4

Step-by-step explanation:

10.6 + x = 15

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3 years ago
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Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter
jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\

since s(t) is the arc length for r(t), which is define as

s(t)=\int\limits^t_0 {||r'(t)||} \, dt

if we substitute the value of r'(t) we arrive at

s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\

s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }

substituting the value of t in to the given vector equation we have

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

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4 years ago
Due in 1 minute please help I-ready
olasank [31]

Answer:

29 1/3

Step-by-step explanation:

All I did was 1760/60 and got that! I hope its right and I hope this helps!!

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SpyIntel [72]

am sorry i forgot the first but the second is transformation and the third is rotation

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3 years ago
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I need help for this question. can someone help me
AlexFokin [52]

Answer:

the missing angle is 130

Step-by-step explanation:

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