Answer:
Yes, this is a valid inference because she took a random sample of the neighborhood.
Step-by-step explanation:
As her survey was non bias and completely random and she found that 15% of the families would participate in the event. She claims that 15% of the neighborhood families would be expected to participate in the sports event. So, yes, this is a valid inference because she took a random sample of the neighborhood.
Answer:12/1
Step-by-step explanation:
I do not completely understand your question, but if you mean area by "murals", then when the width increases, area does, too. For example:
I have a rectangular board that is 5 feet by 3 feet. The area is 15 square feet. I have another board with a longer width, but the same length. It is 5 feet by 4 feet. Its area is 20 square feet.
First, using elimination method for eq. 1 and 2 to eliminate one of the variables.
2x - y + 3z = 8
-2x + 3y - 2z = 10
------------------------------
2y + z = 18
z = 18 - 2y
Now eq. 1 and 3, but multiple eq.1 with 2.
2x + 4y - 2z = 8
-2x + 3y - 2z = 10
----------------------------
7y - 4z = 18
Now you have two new equations 7y -4z = 18 and z = 18 - 2y. Solve for y and z, using substitute method.
7y - 4z = 18
7y - 4(18 - 2y) = 18
7y - 72 + 8y = 18
15y = 18+72
y = 90/15
y = 6
Find z using one of the two new equations.
z = 18 - 2y
z = 18 - 2(6)
z = 18 - 12
z = 6
Now you got y and z, find x using any one of the main three equations.
x + 2y - z = 4
X + 2(6) - 6 = 4
x + 12 - 6 = 4
x = 4 - 6
x = -2
Solutions:
x = -2
y = 6
z = 6
Answer:
13
Step-by-step explanation:
