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2 years ago

Please help I don't know the median give an answer and explanation

Mathematics

1 answer:

morpeh [17]2 years ago

5 0

Answer:

Median is the middle of the data set. For example this data set is 4, 6, 7, 9, 10. First you take out 4 and 10. The you take out 6 and 9 to get a median of 7. But if there is an even amount of numbers like in this data set, 1, 2, 4, 5. Then you take out 1 and 5 and then find the middle point in between 2 and 4 which is 3.

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identify the equation in the point-slope form the line parallel to y=3/4x-4 that passes through (-1,7)

hram777 [196]

Y = 3/4x -4
The slope is 3/4 since it is written in the form y =mx+b where m is the slope
We want a line that is parallel so it will have the same slope
We know the slope of the new line (3/4) and a point (-1,7)
So we can use the point slope form of the equation
y-y1 = m(x-x1)
y-7 = 3/4(x--1)
y-7=3/4(x+1)

4 0

3 years ago

The system shown has _____ solution(s).

loris [4]

This system has one solution. Here are my steps to solving this problem:

y=x+1

2(x+1) - x = 2

2x +2 - x = 2

2x - x + 2 = 2

x + 2 = 2
- 2 - 2
----------------
x = 0

y = 0 + 1
y = 1

I hope this helps you!

5 0

4 years ago

Read 2 more answers

Answer to the question

dangina [55]

Actually , the picture is not complete, will you please upload it again

7 0

4 years ago

What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?

Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:

Equation of Line that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?

Solution:

$x-6y=42$ ..................Given

which can be written as

$y=mx+c$

Where m is the slope of the line

∴ $y=\dfrac{x}{6}-7$

On Comparing we get

$Slope = m = \dfrac{1}{6}$

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

$m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6$

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,

i.e equation in point - slope form

$(y-y_{1})=m(x-x_{1})$

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

$(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line$

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

$6x+y=-5$

3 0

3 years ago

An apple is cut into 6 equal slices. nancy eats 2 of the slices .what fraction of the apple is left.math

ValentinkaMS [17]

Cut the apple into pieces. You get 6/6, which is equal to 1 whole apple. Then after Nancy eats 2 of the slices, you subtract 2/6 from 6/6. After this you get 4/6.
4/6 is the fraction of the apple is left
Not sure if this is high school math though hahah

8 0

3 years ago