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Vladimir79 [104]
3 years ago
6

JAHSHAGAAHSJJSHAGAHSHSHAJSJSJA

Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

1. stop spaming

Step-by-step explanation:

ok so you ha- :L u have 251 plus...

it is easy :D it is 429 then equals 680 :D

i think.

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What is 620000 rounded to the nearest ten thousand
defon
It would stay the same because 2 is lower than 5. Now if it would be 5 and up then it would change but in this case, 4 and lower stays the same. Hope this helps! :)
7 0
4 years ago
Examine the graph of the logarithmic function f(x).
Eduardwww [97]

Answer:

The function f(x) has a vertical asymptote at x = 3

Step-by-step explanation:

We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.

For example, in the case of the natural logarithm, it is not defined for x = 0.

Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)

So a vertical asymptote will be a vertical tendency at a given x-value.

In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)

Then:

The function f(x) has a vertical asymptote at x = 3

6 0
3 years ago
Determine if w = -2 is a solution for the inequality <br> 3w ≤ -12
anastassius [24]
<h3>Answer:   It is <u>not</u> a solution</h3>

======================================================

Explanation:

Plug in w = -2 and simplify.

3w ≤ -12

3(-2) ≤ -12

-6 ≤ -12

The last inequality is false because -6 is neither equal to -12, nor is -6 smaller than -12. Use a vertical number line to see that -6 is above -12, so it should be -12 ≤ -6.

Since -6 ≤ -12 is false, that makes 3w ≤ -12 false when w = -2.

Therefore, w = -2 is <u>not</u> a solution to the given inequality.

7 0
3 years ago
The area of a circular lake is 16 km<br> 2
artcher [175]

Answer:

I can't fix stupid- sorry-

Step-by-step explanation:

3 0
3 years ago
Need answer for this.
cestrela7 [59]

\\ \sf\longmapsto cosV=\dfrac{Base}{Hypotenuse}

\\ \sf\longmapsto cosV=\dfrac{UV}{VT}

  • Put the values

\\ \sf\longmapsto cosV=\dfrac{28}{53}

\\ \sf\longmapsto cosV=0.528

4 0
3 years ago
Read 2 more answers
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