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kompoz [17]
2 years ago
11

3. What is the purpose of a control in a scientific experiment?

Mathematics
1 answer:
s2008m [1.1K]2 years ago
5 0

Answer:  to minimize the effects of variables other than the independent variable (i.e. confounding variables)

Step-by-step explanation:

A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable (i.e. confounding variables). This increases the reliability of the results, often through a comparison between control measurements and the other measurements.

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(1.7 x 10^4) x (8.5 x 10 ^2)
vlabodo [156]

Answer:

144500

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write 12 digit whole numbers with the following digits in correct places
lbvjy [14]

Answer:

29,675,000

Step-by-step explanation:

i’m sorry if this is wrong but i think it’s right

4 0
3 years ago
NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
                            27.5                40.5
40.5-27.5 = 13

The interquartile range is 13.
3 0
3 years ago
Read 2 more answers
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
Car insurance: $12
givi [52]

Answer:

23%

Step-by-step explanation:

First, add all prices together

120.54 + 55.99 + 65.00 = 241.53

Then see what percent 241.53 is of 1,050

23%

Hope this helps! Good luck!

4 0
2 years ago
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