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elixir [45]
4 years ago
12

A 20 inch flat panel computer monitor is on sale for $283.99. It was reduced $53 from the original price. Find the percent reduc

tion in price
Mathematics
1 answer:
charle [14.2K]4 years ago
7 0
The original price before the discount of $53 , was $283.99+$53=$336.99

On the $336.99 he discounted $53 ,

or in percentage discount =(53/336.99)=0.15727 or in % 15.727%
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Jada is making a circular birthday invitation for her friends . The diameter of the circle is 12 cm. She bought 180 cm of ribbon
iVinArrow [24]
She can make 4.

Explanation:

First you gotta find the circumference of the circle which is 37.68

Circumference=Diameter•pi

Pi is 3.14 in case you didn’t know.

Now divide the amount of ribbon she has by the circumference and you get 4.77…

So to make it simple we just say 4 because she wont want to make 4 and a half invitations.

Brainliest my answer if it helps you out?
7 0
4 years ago
Simplify: 14 + 3k = 6k - 7k
Anit [1.1K]
Simplified it is 4k = -14
6 0
3 years ago
Mrs aleaze tells her stuents there will be 50 questions on their test and 20 percent of them will be word problems how much prob
timofeeve [1]
The word problem only gives you two numbers, so it would be easy to assume that the questions involves those two numbers. However, in this case, the question requires that you calculate another answer first: the number of questions Abel got right. You'll need to subtract 4 from 80, then calculate the percentage of the difference:

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6 0
3 years ago
Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.
Nuetrik [128]

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

(x-r_{i})^{m},\,m \le n (1)

Where n is the grade of the polynomial.

Now we proceed to factor the formula:

y = x^{5}-27\cdot x^{2}

y = x^{2}\cdot (x^{3}-27)

y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)

Please notice that x^{2}+3\cdot x + 9 have two complex roots.

y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}  \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3}  \right)\cdot (x-3)

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0
3 years ago
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